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Table 3 Tabulation of Mendel's Phaseolus cross

From: Mendel’s terminology and notation reveal his understanding of genetics

Extended tabulation of expected zygotic ratios in Mendel’s Phaseolus cross

  

\(\frac{{\mathrm{A}}_{1}\;\;{\mathrm{A}}_{2}}{{\mathrm{A}}_{1}\;\;{\mathrm{A}}_{2}}\)

 + 

2

\(\frac{{\mathrm{A}}_{1}\;\;{\mathrm{A}}_{2}}{{\mathrm{a}}_{1}\;\;{\mathrm{ A}}_{2}}\)  

 + 

 

\(\frac{{\mathrm{a}}_{1}\;\;{\mathrm{A}}_{2}}{{\mathrm{a}}_{1}\;\;{\mathrm{ A}}_{2}}\)  

 + 

2

\(\frac{{\mathrm{A}}_{1}\;\;{\mathrm{A}}_{2}}{{\mathrm{A}}_{1}\;\;{\mathrm{a}}_{2}}\)  

 + 

4

\(\frac{{\mathrm{A}}_{1}\;\;{\mathrm{A}}_{2}}{{\mathrm{a}}_{1}\;\;{\mathrm{a}}_{2}}\)  

 + 

2

\(\frac{{\mathrm{a}}_{1}\;\;{\mathrm{A}}_{2}}{{\mathrm{a}}_{1}\;\;{\mathrm{a}}_{2}}\)  

  

\(\frac{{\mathrm{A}}_{1}\;\;{\mathrm{a}}_{2}}{{\mathrm{A}}_{1}\;\;{\mathrm{a}}_{2}}\)  

 + 

2

\(\frac{{\mathrm{A}}_{1}\;\;{\mathrm{a}}_{2}}{{\mathrm{a}}_{1}\;\;{\mathrm{a}}_{2}}\)  

 + 

 

\(\frac{{\mathrm{a}}_{1}\;\;{\mathrm{a}}_{2}}{{\mathrm{a}}_{1}\;\;{\mathrm{a}}_{2}}\)  

Which Mendel explained is equivalent to:

 

1

\({\mathrm{A}}_{1}\;\;{\mathrm{ A}}_{2}\)  

 

2

\({\mathrm{A}}_{1}{{\mathrm{a}}_{1}\;\;\mathrm{ A}}_{2}\)  

 

1

\({\mathrm{a}}_{1}\;\;{\mathrm{ A}}_{2}\)  

 

2

\({\mathrm{A}}_{1}\;\;{\mathrm{ A}}_{2}{\mathrm{a}}_{2}\)  

 

4

\({\mathrm{A}}_{1}{\mathrm{a}}_{1}\;\;{\mathrm{A}}_{2}{\mathrm{a}}_{2}\)  

 

2

\({\mathrm{a}}_{1}\;\;{\mathrm{ A}}_{2}{\mathrm{a}}_{2}\)  

 

1

\({\mathrm{A}}_{1}\;\;{\mathrm{a}}_{2}\)  

 

2

\({\mathrm{A}}_{1} {\mathrm{a}}_{1}\;\;{\mathrm{a}}_{2}\)  

 

1

\({\mathrm{a}}_{1}\;\;{\mathrm{a}}_{2}\)  

Mendel’s actual tabulation:

 

1

\({\mathrm{A}}_{1}\;\;{\mathrm{ A}}_{2}\)  

 

2

\({\mathrm{A}}_{1}{\mathrm{a}}\;\;\mathrm A_{2}\)  

 

1

\({\mathrm{A}}_{2}\;\;a\)  

 

2

\({\mathrm{A}}_{1}\;\;{\mathrm{ A}}_{2}\mathrm{a}\)  

 

4

\({\mathrm{A}}_{1}\mathrm{a}\;\;{\mathrm{A}}_{2}\mathrm{a}\)  

 

2

\({\mathrm{A}}_{2}\mathrm{a\;\;a}\)  

 

1

\({\mathrm{A}}_{1}\;\;\mathrm{a}\)  

 

2

\({\mathrm{A}}_{1}\mathrm{a}\;\;\mathrm{a}\)  

 

1

\(\mathrm{a\;\;a}\)